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10x^2-10x=630
We move all terms to the left:
10x^2-10x-(630)=0
a = 10; b = -10; c = -630;
Δ = b2-4ac
Δ = -102-4·10·(-630)
Δ = 25300
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{25300}=\sqrt{100*253}=\sqrt{100}*\sqrt{253}=10\sqrt{253}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-10\sqrt{253}}{2*10}=\frac{10-10\sqrt{253}}{20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+10\sqrt{253}}{2*10}=\frac{10+10\sqrt{253}}{20} $
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